To Lc3 Or How In
1 answer1. active oldest votes. 2. you could use demorgan's law to gain this. x ∨ y = ¬ (¬x ∧ ¬y) in lc3 code it's: ld r1, a ;flow the price of a into r1 ld r2, b ;move the value of b into r2 not r1, r1 now not r2, r2 and r3, r1, r2 not r3, r3 halt. share. Slides: www. slideshare. net/nordinabouzahra/lc3-assembly-reading-strings errata: slide 9, places should be out across the eight:17 mark i say unlawful instru. Thanks for contributing a solution to stack overflow! please be sure to reply the question. provide info and share your research! but keep away from soliciting for assist, clarification, or responding to different solutions. making statements based totally on opinion; returned them up with references or non-public enjoy. to learn greater, see our recommendations on writing tremendous. See more videos for how to or in lc3. How am i able to write a easy lc-3 application that compares the 2 numbers in r1 and r2 and puts the price 0 in r0 if r1 = r2, 1 if r1 > r2 and -...